题目:(gsfxj222)设 222 : Dxya +£ ,当 a = ( )时, 222 222 xya axydxdy p +£ –= òò
1
3 3 2
3 3 4
3 1 2
题目:(gsfxj222)设 222 : Dxya +£ ,当 a = ( )时, 222 222 xya axydxdy p +£ –= òò
1
3 3 2
3 3 4
3 1 2